Asked by Sara
Find the following inequality.
15(x^2-1)>16x
15(x^2-1)>16x
Answers
Answered by
Steve
is it lost? You must mean "solve" the inequality
15(x^2-1)>16x
15x^2 - 16x - 15 > 0
(5x+3)(3x-5) > 0
If the product is positive, either both are positive, or both are negative. So,
x < -3/5 or x > 5/3
15(x^2-1)>16x
15x^2 - 16x - 15 > 0
(5x+3)(3x-5) > 0
If the product is positive, either both are positive, or both are negative. So,
x < -3/5 or x > 5/3
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