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NOTE: this is for advanced functions, NOT physics A 2m length of board rests with one end on the floor and the other end on a s...Asked by Thomson
NOTE: this is for advanced functions, NOT physics
A 2m length of board rests with one end on the floor and the other end on a small stack of bricks. A baseball is rolled up the board and back down again in a total of 4 seconds. The farthest the baseball reached on the board was 130cm.
Draw a graph of this. [distance time]
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I would appreciate it if someone could tell me the general shape or link me to a graph made on a graphing site.
A 2m length of board rests with one end on the floor and the other end on a small stack of bricks. A baseball is rolled up the board and back down again in a total of 4 seconds. The farthest the baseball reached on the board was 130cm.
Draw a graph of this. [distance time]
---
I would appreciate it if someone could tell me the general shape or link me to a graph made on a graphing site.
Answers
Answered by
Steve
well, it's a parabola, with
y(0) = 0
y(4) = 0
so we know that the max height is reached at y=2.
y(2) = 130
so, the vertex is at (2,130)
y(t) = -a(t-2)^2 + 130
Now, we know that y(0) = 0, so
0 = -a(4)+130
a = 130/4
y(t) = -130/ (t-2)^2 + 130
visit http://rechneronline.de/function-graphs/
and type in
-130/4 * (x-2)^2 + 130
set the x interval to 0,4
and y to 0,150
and you will see the graph
y(0) = 0
y(4) = 0
so we know that the max height is reached at y=2.
y(2) = 130
so, the vertex is at (2,130)
y(t) = -a(t-2)^2 + 130
Now, we know that y(0) = 0, so
0 = -a(4)+130
a = 130/4
y(t) = -130/ (t-2)^2 + 130
visit http://rechneronline.de/function-graphs/
and type in
-130/4 * (x-2)^2 + 130
set the x interval to 0,4
and y to 0,150
and you will see the graph
Answered by
Thomson
Thank you.
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