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Asked by
Travis
If f(3)=−3, g(3)=9, f′(3)=1, and g′(3)=2,
Find (f/(f−g))′(3).
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Answered by
Steve
(f/(f-g))' = [f'(f-g) - f(f'-g')]/(f-g)^2
= [(1)(-3-9) - (-3)(1-2)]/(-3-9)^2
= -5/48
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