mols Na2CrO4 = grams/molar mass
M = mols/L soln
M = mols/L soln
First, we need to convert the given mass of Na2CrO4 into moles. The molar mass of Na2CrO4 is calculated by summing the atomic masses of its constituent elements:
Molar mass of Na2CrO4 = (2 * Atomic mass of Na) + Atomic mass of Cr + (4 * Atomic mass of O)
= (2 * 22.99 g/mol) + 52.00 g/mol + (4 * 16.00 g/mol)
= 161.97 g/mol
Now we can calculate the number of moles of Na2CrO4:
Number of moles = Given mass / Molar mass
= 16.0 g / 161.97 g/mol
≈ 0.0988 mol
Next, we need to convert the given volume of solution into liters:
Volume of solution = 555 mL = 555 mL * (1 L / 1000 mL)
= 0.555 L
Finally, we can calculate the molarity:
Molarity (M) = Number of moles / Volume of solution
= 0.0988 mol / 0.555 L
≈ 0.178 M
Therefore, the molarity of the solution is approximately 0.178 M.