A parallelogram ABCD has perimeter equal to 124. Let E be the foot of the perpendicular from A to BC, and let F be the foot of the perpendicular from A to CD. If AE=7 and AF=24, what is the area of the parallelogram?

3 answers

since area = base * height,
oops. hit wrong key.

24*AB = 7*BC
but AB+BC = 124/2 = 62, so
24(62-BC) = 7BC
BC = 48
AB = 14
Area = 24*14 = 7*48 = 336
thank you