z = (x - 32)/1.2
For 1: you have to use a z-table to find the value where 99% of the values are less than that number meaning that there is 1% in the upper tail. Z-tables to differ from book to book, be sure to read it carefully.
Once you have that z- value, substitute it into the formula above and solve for x.
For #2, you are trying to find the values for the middle 50%. That means you will have 25% in each tail or .25.
Take that z-score and multiply it by the SD. This will give you that you would add or subtract from 32 mm.
The lengths of the eggs of a species of bird are roughly normally distributed, with a mean of 32 mm and an SD of 1.2 mm.
1.Approximately what is the 99th percentile of the lengths? Give your answer in mm but please do not enter the units.
2.Approximately 50% of the eggs have lengths in the range 32 mm plus or minus ____________ mm.
3 answers
26.46
it is not working , can u plz do it for me
3 answers