Find the equation of the line that goes through the given point
and has the given slope and has the given slope. Write the answer in slope-intercept (-1, -5), -8
1. m = 3 (0,4)
s=B4=3
si=3x+4
ps=y-4=3x
Are we doing these correctly?
I do not know what those forms mean, but if the line goes through (0,4) with slope 3, the equation is
y - 4 = 3 x
y = 3x + 4
which agrees with you "si"
I do not know what those forms mean, but if the line goes through (0,4) with slope 3, the equation is
y - 4 = 3 x
y = 3x + 4
which agrees with you "si"
and has the given slope and has the given slope. Write the answer in slope-intercept (-1, -5), -8
In this case, the given slope is 3 and the line passes through the point (0, 4). To find the equation in slope-intercept form, you can substitute the values of the slope and the coordinates of the point into the equation.
To write the equation in standard form, which is Ax + By = C, we can rearrange the equation y = 3x + 4 as -3x + y = 4, or you can multiply both sides of the equation by -1 to get -y = -3x - 4.
To write the equation in point-slope form, which is y - y1 = m(x - x1), where (x1, y1) is a point on the line, you can substitute the values of the slope and the coordinates of the point into the equation. In this case, it would be y - 4 = 3(x - 0), which simplifies to y - 4 = 3x.
So, the equation of the line in standard form is -y = -3x - 4, the equation in slope-intercept form is y = 3x + 4, and the equation in point-slope form is y - 4 = 3x.