Asked by John
Find the largest possible real value of
\sqrt{(x-20)(y-x)} + \sqrt{(140-y)(20-x)} + \sqrt{(x-y)(y-140)}
subject to -40\leq x \leq 100 and -20\leq y \leq 200.
\sqrt{(x-20)(y-x)} + \sqrt{(140-y)(20-x)} + \sqrt{(x-y)(y-140)}
subject to -40\leq x \leq 100 and -20\leq y \leq 200.
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