Asked by Jennifer
you trim a large square picture so that you could fit it into a frame. you trim 3 inches from the length and 2 inches from the width. the area of the resulting picture is 56sq in what was the perimeter of the original large square picture?
Answers
Answered by
Reiny
Let the original square be x by x inches
after trimming,
the length is x-4 and the width is x-6
area = (x-4)(x-6) = 56
x^2 - 10x + 24 = 56
x^2 - 10x <b>+ 25 </b> = 56-24 <b>+ 25 </b>
(x-5)^2 = 57
x-5 = ±√57
x = 5 +√57 or a negative
perimeter of original square = 4(5+√57) = appr 50.2 inches
after trimming,
the length is x-4 and the width is x-6
area = (x-4)(x-6) = 56
x^2 - 10x + 24 = 56
x^2 - 10x <b>+ 25 </b> = 56-24 <b>+ 25 </b>
(x-5)^2 = 57
x-5 = ±√57
x = 5 +√57 or a negative
perimeter of original square = 4(5+√57) = appr 50.2 inches
Answered by
Robert
So you actually have to use the Pythagoras theorem. The use of imaginary number divided by the contagion of 71. Professor at Langster College.
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