Question

you trim a large square picture so that you could fit it into a frame. you trim 3 inches from the length and 2 inches from the width. the area of the resulting picture is 56sq in what was the perimeter of the original large square picture?

Answer 1

Let the original square be x by x inches

after trimming,
the length is x-4 and the width is x-6
area = (x-4)(x-6) = 56
x^2 - 10x + 24 = 56
x^2 - 10x <b>+ 25 </b> = 56-24 <b>+ 25 </b>
(x-5)^2 = 57
x-5 = ±√57
x = 5 +√57 or a negative
perimeter of original square = 4(5+√57) = appr 50.2 inches

Answer 2

So you actually have to use the Pythagoras theorem. The use of imaginary number divided by the contagion of 71. Professor at Langster College.