Asked by Ally
The legs of an isosceles triangle measures 2x^4+2x-1 units. The perimeter of the triangle is 5x^4-2x^3+x-3 units. Write a polynomial that represents the measure of the base of the triangle.
Answers
Answered by
Lena
Perimeter = S1 + S2 + S3
5x^4-2x^3+x-3= (2x^4 + 2x-1) + (2x^4+2x-1) + base
5x^4-2x^3+x-3 = 2(2x^4 + 2x-1)+ base
5x^4-2x^3+x-3 - 2(2x^4 + 2x-1) = BASE
5x^4-2x^3+x-3 -4x^4-4x+2= BASE
5x^4-4x^4-2x^3-3x-1 = BASE
5x^4-2x^3+x-3= (2x^4 + 2x-1) + (2x^4+2x-1) + base
5x^4-2x^3+x-3 = 2(2x^4 + 2x-1)+ base
5x^4-2x^3+x-3 - 2(2x^4 + 2x-1) = BASE
5x^4-2x^3+x-3 -4x^4-4x+2= BASE
5x^4-4x^4-2x^3-3x-1 = BASE
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