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Can someone start me off on these and please explain step by step how you got everything because I'm having difficulty understa...Asked by Alex
Can someone start me off on these and please explain step by step how you got everything because I'm having difficulty understanding the entire concept.
Find the projection of u onto v and calculate its magnitude.
a) u = (2,5) v = (6,4)
b) u = (3, 6, -2) v = (-4, 3, 8)
2) If u and v are non zero vectors, but Projection (u unto v) = 0, what conclusion can be drawn?
Would that also mean Projection (v unto u) = 0?
3) Find the projection of PQ onto each of the coordinate axes, where point (2,3,5) and Q is the point (-1,2,5).
Find the projection of u onto v and calculate its magnitude.
a) u = (2,5) v = (6,4)
b) u = (3, 6, -2) v = (-4, 3, 8)
2) If u and v are non zero vectors, but Projection (u unto v) = 0, what conclusion can be drawn?
Would that also mean Projection (v unto u) = 0?
3) Find the projection of PQ onto each of the coordinate axes, where point (2,3,5) and Q is the point (-1,2,5).
Answers
Answered by
Reiny
The projection of vector u onto vector v is defined as
(u∙v)/│v│
u∙v = (2,5)∙(6,4) = 12+20 = 32
│v│ = √(6^2+4^2) = √52
so the projection of u onto v
= 32/√52 = 16/√13
follow this method for the other questions.
Think of the "projection of u onto v" as the 'shadow' cast by u onto v by a light from above shining perpendicular to v.
So if u does not cast a shadow on v, (the projection is zero), what should that tell you about the direction of u in relation to v ??
(u∙v)/│v│
u∙v = (2,5)∙(6,4) = 12+20 = 32
│v│ = √(6^2+4^2) = √52
so the projection of u onto v
= 32/√52 = 16/√13
follow this method for the other questions.
Think of the "projection of u onto v" as the 'shadow' cast by u onto v by a light from above shining perpendicular to v.
So if u does not cast a shadow on v, (the projection is zero), what should that tell you about the direction of u in relation to v ??
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