Asked by Joe
                A 2 feet piece of wire is cut into two pieces and once piece is bent into a square and the other is bent into an equilateral triangle. How much wire should be used for the square to ensure that the total area enclosed by both shapes is minimized?
            
            
        Answers
                    Answered by
            Steve
            
    if the triangle has side a, and the square has side b,
3a+4b=2
The total area is
A = (1/2)(a/2)(a/2 √3) + b^2
16A = 2√3 a^2 + (4b)^2
= 2√3 a^2 + (2-3a)^2
16 dA/da = 4√3 a - 6(2-3a)
dA/da = 0 when a = 6/(9+2√3)
    
3a+4b=2
The total area is
A = (1/2)(a/2)(a/2 √3) + b^2
16A = 2√3 a^2 + (4b)^2
= 2√3 a^2 + (2-3a)^2
16 dA/da = 4√3 a - 6(2-3a)
dA/da = 0 when a = 6/(9+2√3)
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.