Let |ψ> = a|0>+b|1> where a and b are nonnegative real numbers. We know that if we apply H to this qubit and then measure the resulting state in the sign basis, the probability of getting a + is 1/4
(a) What is |ψ> in the standard basis?
|0> =
|1> =
(b) What is |ψ> in the sign basis?
|+>
|->
13 answers
does anyone know the answer
a) 1/2 + sqrt(3)/2
b) (1+sqrt(3))/(2*sqrt(2))
(1-sqrt(3))/(2*sqrt(2))
(1-sqrt(3))/(2*sqrt(2))
a) What quantum state do you have to input in order to get output |00⟩ ?
b) What quantum state do you have to input in order to get output |11⟩ ?
b) What quantum state do you have to input in order to get output |11⟩ ?
(c) What quantum state do you have to input in order to get output 1/2sqrt(|00⟩+|11⟩)?
Please answer someone!
what is the answer for these:
(a) What is |ψ> in the standard basis?
|0> =
|1> =
(a) What is |ψ> in the standard basis?
|0> =
|1> =
a) 1/sqrt(2) 0
0 1/sqrt(2)
0 1/sqrt(2)
b)0 1/sqrt(2)
-1/sqrt(2) 0
c)1/2 1/2
-1/2 1/2
-1/sqrt(2) 0
c)1/2 1/2
-1/2 1/2
answer for this please:
Let |ψ> = a|0>+b|1> where a and b are nonnegative real numbers. We know that if we apply H to this qubit and then measure the resulting state in the sign basis, the probability of getting a + is 1/4
(a) What is |ψ> in the standard basis?
|0> =
|1> =
Let |ψ> = a|0>+b|1> where a and b are nonnegative real numbers. We know that if we apply H to this qubit and then measure the resulting state in the sign basis, the probability of getting a + is 1/4
(a) What is |ψ> in the standard basis?
|0> =
|1> =
What is the matrix (4x4) for ZX (Z applied on the first qubit and X applied on the second qubit)?
C) is wrong?
please a answer for this:
What is the matrix (4x4) for ZX (Z applied on the first qubit and X applied on the second qubit)?
What is the matrix (4x4) for ZX (Z applied on the first qubit and X applied on the second qubit)?