24^2 + b^2 = 25^2
576 + b^2 = 625
b^2 = 625 - 576
b^2 = 49
b = 7 feet
Please show work.
576 + b^2 = 625
b^2 = 625 - 576
b^2 = 49
b = 7 feet
Let's call the distance the bottom of the ladder should be placed from the building "x". We can set up the following equation:
x^2 + 24^2 = 25^2
Simplifying the equation:
x^2 + 576 = 625
Subtracting 576 from both sides:
x^2 = 49
Taking the square root of both sides:
x = √49
x = 7
So, the bottom of the ladder should be placed 7 ft away from the building.
In this case, the ladder represents the hypotenuse, and the distance from the building to the bottom of the ladder represents one of the legs. The vertical distance from the ground to the window represents the other leg.
Let's denote the distance from the building to the bottom of the ladder as x. According to the problem, the ladder is 25 ft long, and the window is 24 ft above the ground.
Using the Pythagorean theorem, we have:
x^2 + 24^2 = 25^2
Simplifying the equation:
x^2 + 576 = 625
Subtracting 576 from both sides:
x^2 = 625 - 576
x^2 = 49
Taking the square root of both sides, we find:
x = √49
x = 7
Therefore, the bottom of the ladder should be placed 7 ft away from the building.