Asked by tmouery
A cylindrical water tower with a conical top and hemispheric bottom needs to be painted. If the cost is 2.19 per square foot, how much does it cost (to the nearest dollar) to paint the tank?
Answers
Answered by
Reiny
surface area of tower
= surface area of "sleeve" of cylinder + half a sphere + lateral surface area of cone
Since you don't give me any dimensions, that is all I can give you.
= surface area of "sleeve" of cylinder + half a sphere + lateral surface area of cone
Since you don't give me any dimensions, that is all I can give you.
Answered by
tmouery
Oops, sorry, I forgot to give the dimensions.
The dimensions of the cone are 2ft. high and 3.2 ft. at the slant.
The dimensions of the cylinder are 5ft. across and 6 ft. tall.
I wasn't sure if I needed to figure Total Surface Area or Lateral Surface Area, or both.
The dimensions of the cone are 2ft. high and 3.2 ft. at the slant.
The dimensions of the cylinder are 5ft. across and 6 ft. tall.
I wasn't sure if I needed to figure Total Surface Area or Lateral Surface Area, or both.