[ a^(4/3) c^(1/6) (1/9)b^-3 ]^-2
= [ a^(-8/3) c^(-1/3) (81) b^6 ]
I can not follow you after that, sorry
* Simplify.
a to the power of 4/3 times c ^1/6 all over 9b^3..... everything is in the parenthesis and is raised to the power of -2....times the whole thing to,
a to the power of 3 times b to the power of two all over 3c.... everything is in the parenthesis and is raised to -1/4
******Is the answer (3^17/4)(b^11/2) all over (a^41/12)(c^1/12) ?
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