Asked by StressedStudent
The equilibrium bond length of 1
H35Cl is 126 pm. What is wavelength of the required electromagnetic radiation to excite the rotational state from j=1 to j=2?
The masses of 1H and 35Cl are 1.0078 amu and 34.9689 amu, respectively)
H35Cl is 126 pm. What is wavelength of the required electromagnetic radiation to excite the rotational state from j=1 to j=2?
The masses of 1H and 35Cl are 1.0078 amu and 34.9689 amu, respectively)
Answers
Answered by
DrBob222
Here is a site that spells that out.
Using m1 and m2 you can calculate the reduced mass,u, with u and R you can calculate I (moment of inertia), knowing I allows you to calculate B. Knowing J and B allows you to calculate E. Then E = hc/wavelength and wavelength can be determined.
http://hyperphysics.phy-astr.gsu.edu/%E2%80%8Chbase/molecule/rotrig.html#c3
Using m1 and m2 you can calculate the reduced mass,u, with u and R you can calculate I (moment of inertia), knowing I allows you to calculate B. Knowing J and B allows you to calculate E. Then E = hc/wavelength and wavelength can be determined.
http://hyperphysics.phy-astr.gsu.edu/%E2%80%8Chbase/molecule/rotrig.html#c3
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