Asked by Cymi
Rewrite the relation as a function of x
4y+cubed root^x=(x-2)^2
4y+cubed root^x=(x-2)^2
Answers
Answered by
Steve
4y+∛x = (x-2)^2
4y = (x-2)^2 - ∛x
y = ((x-2)^2 - ∛x)/4
4y = (x-2)^2 - ∛x
y = ((x-2)^2 - ∛x)/4
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.