Asked by tmouery
A swimming pool is in the form of a semicircular figure. Its width is 20 ft. and that parallel portions of the sides are each 20 ft. What is the are of a 5-ft-wide walk surrounding the pool? Round to the tenths.
Answers
Answered by
Steve
what "sides" of a semicircle are parallel? Do you mean the circle has a diameter of 20 ft? If the base is 20 ft, then that would be the diameter of the circle.
Assuming that, we have a pool with area 1/2 pi * 10^2 = 50pi ft^2
Increase the radius by 5 ft, and you have an area of 1/2 pi * 15^2 = 225/2 pi
So, the area of the walk is 125/2 pi = 196.4 ft^2
If I have interpreted the dimensions incorrectly, fix my error and redo the calculation.
Assuming that, we have a pool with area 1/2 pi * 10^2 = 50pi ft^2
Increase the radius by 5 ft, and you have an area of 1/2 pi * 15^2 = 225/2 pi
So, the area of the walk is 125/2 pi = 196.4 ft^2
If I have interpreted the dimensions incorrectly, fix my error and redo the calculation.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.