Oxidation of bis(bipyridine) copper (I) ion by molecular oxygen is described by the equation:

Question

Cu(C10H8N2)2+(aq) + O2(aq) ----products
The reaction is first order in oxygen and second order in Cu(C10H8N2)2+

(a) Write the rate law
(b) What is the overall reaction order?
(c) How does the reaction rate change if the concentration of Cu(C10H8N2)2+ is decreased by a factor of 4?

Answer 1

a.
rate = k(O2)[Cu(C10H8N2)2]^2

b.
2+1 = 3

c.
4^2 = 16 so decreasing by a factor of 4 would make it 1/16 the original rate.