Asked by Sabrina P
Oxidation of bis(bipyridine) copper (I) ion by molecular oxygen is described by the equation:
Cu(C10H8N2)2+(aq) + O2(aq) ----products
The reaction is first order in oxygen and second order in Cu(C10H8N2)2+
(a) Write the rate law
(b) What is the overall reaction order?
(c) How does the reaction rate change if the concentration of Cu(C10H8N2)2+ is decreased by a factor of 4?
Cu(C10H8N2)2+(aq) + O2(aq) ----products
The reaction is first order in oxygen and second order in Cu(C10H8N2)2+
(a) Write the rate law
(b) What is the overall reaction order?
(c) How does the reaction rate change if the concentration of Cu(C10H8N2)2+ is decreased by a factor of 4?
Answers
Answered by
DrBob222
a.
rate = k(O2)[Cu(C10H8N2)2]^2
b.
2+1 = 3
c.
4^2 = 16 so decreasing by a factor of 4 would make it 1/16 the original rate.
rate = k(O2)[Cu(C10H8N2)2]^2
b.
2+1 = 3
c.
4^2 = 16 so decreasing by a factor of 4 would make it 1/16 the original rate.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.