6t^2+21t-12

Question

Factor the expression

I don't know how to figure it out

Answer 1

I used the quadratic formula
for
6t^2+21t-12 = 0

t = [ -21 +/- sqrt(441+228) ]/12

= [ -21 +/- 27 ] /12

= 1/2 or -4

so
(x+4) and (2x -1) are factors
so try
3 (x+4)(2x-1)

Answer 2

Of course if I were a little smarter I would factor 3 out to start

3(2t+7t-4)

3 (t+4)(2t-1)

Answer 3

Thank you

Answer 4

Factor completely and then place the factors in the proper location on the grid.4y2 + 25y + 6