Asked by zandile
The sum of the first 10 terms of an arithmetic series is 145 and the sum of its fourth and ninth term is five times the third the..determine the first term and constant difference
Answers
Answered by
Steve
10/2(2a+9d) = 145
a+3d + a+8d = 5(a+2d)
a=1
d=3
a+3d + a+8d = 5(a+2d)
a=1
d=3
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