Asked by anne
the perimeter of a rectangle is 40 feet and its area is 96 square feet. find the length and width?
Answers
Answered by
PsyDAG
2L + 2W = 40
Divide both sides of first equation by 2.
L + W = 20, Then W = 20 - L
L * W = 96
Substitute 20-L for W in second equation and solve for L. Insert that value into the first equation and solve for W. Check by inserting both values into the second equation.
Divide both sides of first equation by 2.
L + W = 20, Then W = 20 - L
L * W = 96
Substitute 20-L for W in second equation and solve for L. Insert that value into the first equation and solve for W. Check by inserting both values into the second equation.
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