At present a woman is twice as old as her daughhter, twenty one years ago she was 3 times older than her daughter

Question

Hint: ket x be the daughters current age

Answer 1

First we represent the unknowns:
Let x = daughter's present age
Let 2x = mother's present age

According to the problem, 20 years ago, the mother was three times older than her daughter. Thus,
2x - 20 = 3(x - 20)
Solving for x,
2x - 20 = 3x - 60
2x - 3x = -60 + 20
-x = -40
x = 40 years old (daughter, present age)
2x = 80 years old (mother, present age)

hope this helps~ :)

Answer 2

thankss alot :D

Answer 3

Actually it was 21 years ago...

Answer 4

But i get it thanks :)