Asked by Rayyan
(2c-d)/(c^2d)+(c+d)/(cd^2)
Answers
Answered by
Reiny
LCD = c^2 d^2
(2c-d)/(c^2d)+(c+d)/(cd^2)
= ( d(2c-d) + c(c+d))/(c^2d^2)
= (2cd - d^2 + c^2 + cd)/(c^2d^2)
= (3cd - d^2 + c^2)/(c^2d^2)
You did not say what you want done with it.
(2c-d)/(c^2d)+(c+d)/(cd^2)
= ( d(2c-d) + c(c+d))/(c^2d^2)
= (2cd - d^2 + c^2 + cd)/(c^2d^2)
= (3cd - d^2 + c^2)/(c^2d^2)
You did not say what you want done with it.
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