Solve the problem above.
Responses
A 100.66100.66
B 74.274.2
C –74.2–74.2
D 112.31
3 answers
To solve the problem \( 87.43 - (-13.23) \), we need to remember that subtracting a negative number is the same as adding its positive counterpart. Thus, the expression simplifies to:
\[ 87.43 + 13.23 \]
Now, we perform the addition:
\[ 87.43 + 13.23 = 100.66 \]
Therefore, the answer is \( 100.66 \).
The correct response is A: 100.66.
To solve \( 2 \frac{3}{4} - (-1 \frac{1}{3}) \), first, we recognize that subtracting a negative is the same as adding the positive:
\[ 2 \frac{3}{4} + 1 \frac{1}{3} \]
Next, we convert both mixed numbers to improper fractions:
For \( 2 \frac{3}{4} \): \[ 2 \frac{3}{4} = \frac{2 \times 4 + 3}{4} = \frac{8 + 3}{4} = \frac{11}{4} \]
For \( 1 \frac{1}{3} \): \[ 1 \frac{1}{3} = \frac{1 \times 3 + 1}{3} = \frac{3 + 1}{3} = \frac{4}{3} \]
Now we have:
\[ \frac{11}{4} + \frac{4}{3} \]
Next, we need a common denominator to add these fractions. The least common multiple of 4 and 3 is 12.
Convert each fraction:
For \( \frac{11}{4} \): \[ \frac{11}{4} = \frac{11 \times 3}{4 \times 3} = \frac{33}{12} \]
For \( \frac{4}{3} \): \[ \frac{4}{3} = \frac{4 \times 4}{3 \times 4} = \frac{16}{12} \]
Now, we can add the two fractions:
\[ \frac{33}{12} + \frac{16}{12} = \frac{33 + 16}{12} = \frac{49}{12} \]
Now we can convert \( \frac{49}{12} \) back to a mixed number. \( 49 \div 12 \) gives us 4 with a remainder of 1.
So,
\[ \frac{49}{12} = 4 \frac{1}{12} \]
Therefore, the final answer is:
\[ 4 \frac{1}{12} \]
The correct response is A: 4 and 1 over 12.
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