Question

Please help me.
Solve the system algebraically.
16)y=x^3+x^2
y=3x^2

Answer 1

since both equations = y, you can set each equation next to each other.

x^3 +x^2 = 3x^2

Subtract 3x^2 from each side.

x^3 -2x^2 = 0

Factor out the GCF

2x^2 (x - 1) = 0

2x^2 = 0 x - 1 = 0

solve for x.

then find y in one of the original equations once you know x.