Asked by barotseland network
A resistor of 15 ohms and an inductor of 4H and capacitor of 25 micro F are connected in series across 230V AC supply calculate.
a.The frequency
b.current
c.voltage drop or pd across inductance.
a.The frequency
b.current
c.voltage drop or pd across inductance.
Answers
Answered by
Henry
I cannot calculate the freq. unless the reactance of the inductor or capacitor is given. I will assume a 230v.- 60 Hz supply.
a 60 Hz.
b. Xl = 2pi*F*L = 6.28*60*4 = 1508 Ohms.
Xc = 1/(2p*F*C) = 1/(6.28*60*25*10^-6=
106 Ohms.
Z = R + j(Xl-Xc)
Z = 15 + j(1508-106)
Z = 15 + j1402 = Rectangular form.
tanA = Xl/R = 1402/15 = 93.5
A = 89.4o
Z = Xl/sinA = 1402/sin89.4=1402.1 Ohms
@ 89.4o = Polar form.
I = V/Z = 230/1402.1=0.164A @ (-89.4o)
c. V = I * Xl = 0.164 * 1508 = 247.3 V.
a 60 Hz.
b. Xl = 2pi*F*L = 6.28*60*4 = 1508 Ohms.
Xc = 1/(2p*F*C) = 1/(6.28*60*25*10^-6=
106 Ohms.
Z = R + j(Xl-Xc)
Z = 15 + j(1508-106)
Z = 15 + j1402 = Rectangular form.
tanA = Xl/R = 1402/15 = 93.5
A = 89.4o
Z = Xl/sinA = 1402/sin89.4=1402.1 Ohms
@ 89.4o = Polar form.
I = V/Z = 230/1402.1=0.164A @ (-89.4o)
c. V = I * Xl = 0.164 * 1508 = 247.3 V.
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