Question

Please help with this:
Write a polynomial in standard from with the zeros -2, -2 and 2.
I remember that (x-a)(x-b)(x-c)=0 but I forget what exactly to do.

Answer 1

x = -2 so x+2 = 0
x = -2 so x +2 =0
x = 2 so x -2 = 0

(x+2)(x+2)(x-2) =0

You have to multiply (x+2)(x+2)

Then multiply that trinomial by (x-2)

Or you could multiply (x+2)(x-2) first this might be quicker because it is the sum and difference. Then multiply that answer times (x+2)