Asked by bryan
At 2:00 PM a car's speedometer reads 30 mi/h. At 2:10 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:10 the acceleration is exactly 120 mi/h^2.
Answers
Answered by
Steve
The average acceleration is (50-30)/(1/6) = 120
Since velocity is continuous, the mean value theorem guarantees that the stipulated condition exists. Maybe everywhere, but surely somewhere.
Since velocity is continuous, the mean value theorem guarantees that the stipulated condition exists. Maybe everywhere, but surely somewhere.
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