Asked by breseida
An aqueous solvent of NaCl has a melting point of –165C
How many moles of NaCl are present in a 189 g solvent?
How many moles of NaCl are present in a 189 g solvent?
Answers
Answered by
bobpursley
I don't believe your numbers. -165C as the freezing point is a pretty great amount of salt.
freezingpoint=molarity*-.52
molarity=165/.52 about 300 moles/kg solvent
molesNaCl=about 300/.189 about 1600 moles salt or about more than a barrel full of salt in a beaker of water? It isn't going to happen, at least here in Texas.
freezingpoint=molarity*-.52
molarity=165/.52 about 300 moles/kg solvent
molesNaCl=about 300/.189 about 1600 moles salt or about more than a barrel full of salt in a beaker of water? It isn't going to happen, at least here in Texas.
Answered by
DrBob222
Actually it is even worse than that since Kf is 1.86 (and not 0.52)
Answered by
bobpursley
True.
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