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John
x and y satisfy 2^x = 5 and 5 ^ y = 64. What is the value of xy?
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Answered by
Damon
x log 2 = log 5
y log 5 = log 2^6 = 6 log 2
so
x y log 2 log 5 = 6 log 5 log 2
or
xy = 6
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