Asked by hannah
Phenylacetic acid (C6H5CH2COOH) is one of the substances that accumulates in the blood of people with phenylketonuria, an inherited disorder that can cause mental retardation or even death. A 0.021 M solution of C6H5CH2COOH has a pH of 2.99. Calculate the Ka value for this acid.
what equation do i use?
what equation do i use?
Answers
Answered by
DrBob222
Call that long name HP (which doesn't have anything to do with pH).
pH = 2.99
2.99 = -log(H^+)
(H^+) = 0.00102
.........HP ==> H^+ + P^-
I.....0.021.....0......0
C........-x.....x.....x
E......0.021-x..x.....x
Ka = (H^+)(P^-)/(HP)
Substitute 0.00102 for x and 0.021-0.00102 for HP and solve for Ka.
pH = 2.99
2.99 = -log(H^+)
(H^+) = 0.00102
.........HP ==> H^+ + P^-
I.....0.021.....0......0
C........-x.....x.....x
E......0.021-x..x.....x
Ka = (H^+)(P^-)/(HP)
Substitute 0.00102 for x and 0.021-0.00102 for HP and solve for Ka.
Answered by
Groat Daddy
Whi i get fired tho
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.