Asked by Abhishek
a beam of light consisting of two wavelengths 800nm and 600 nm is used to obtain the interference pattern in youngs double slit expt on a screen placed 1.4m away.if two slits are separated by 0.28mm,calculate the least distance from the central bright maximum where the bright fringes of the two wavelenghts coinside..? plz help
Answers
Answered by
Steve
for the 600nm wavelength, then nth fringe occurs at
n*600*10^-9m * 1400mm/.28mm = n*.003m
for the 800 nm, it's n*.004m
So, the first coincidence is at .012m
This is discussed in an identical problem at
http://www.physicsforums.com/showthread.php?t=364763
n*600*10^-9m * 1400mm/.28mm = n*.003m
for the 800 nm, it's n*.004m
So, the first coincidence is at .012m
This is discussed in an identical problem at
http://www.physicsforums.com/showthread.php?t=364763
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