at the top of the bump it stops rolling and stops going forward (teeters motionless)
Thus at the top the kinetic energy is zero and the potential energy is m g (r+h)
At the bottom the potential energy is m g r
so it gained potential energy of m g h
That is how much kinetic energy it lost
Ke = .5 m v^2 + .5 I w^2
I = m r^2
w = v/r
so in terms of v
Ke = .5 m v^2 + .5 m r^2 (v^2/r^2)
Ke = m v^2 total (half translational and half rotational)
so
m v^2 = m g h
v = sqrt (g h)
If a hollow metal cylinder of radius r is rolling towards a circular bump of height h.
calculate the minimum speed needed to progress over a circular bump.
1 answer
1 answer