Asked by fatimah
                A race car travels northward on a straight, level track at a constant speed travels 0.745 km in 22.0 s. The return trip over the same track is made in 27.0 s.
(a) What is the average velocity of the car in m/s for the first leg of the run?
m/s
(b) What is the average velocity for the total trip?
m/s
            
        (a) What is the average velocity of the car in m/s for the first leg of the run?
m/s
(b) What is the average velocity for the total trip?
m/s
Answers
                    Answered by
            Dr. Jane
            
    Distance = velocity x time
.745 = velocity x 22
divide both sides by 22 to get the velocity for the first leg.
.745 = velocity x 27
do the same to get the velocity for the second leg.
to get the average: add the two velocities and divide by two.
    
.745 = velocity x 22
divide both sides by 22 to get the velocity for the first leg.
.745 = velocity x 27
do the same to get the velocity for the second leg.
to get the average: add the two velocities and divide by two.
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