Asked by Anonymous
what is the volume occupied by a mixture of 25.7 g of NO2 and 13.9g of SO2 at STP
Answers
Answered by
DrBob222
mols SO2 = grams/molar mass
mols NO2 = grams/molar mass
Total mols = mols SO2 + mols NO2.
Then use PV = nRT and calculate volume in L.
mols NO2 = grams/molar mass
Total mols = mols SO2 + mols NO2.
Then use PV = nRT and calculate volume in L.
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