Asked by Anonymous
A package slides down a 135 m long ramp with no friction. If the package starts from rest at the top and is to have a speed no faster than 19m/s at the bottom, what should be the maximum angle of inclination?
Answers
Answered by
drwls
(1/2) M Vmax^2 = M*g*135 sinA
M cancels out.
sinA = (1/2)Vmax^2/(g*135)
= 0.1364
A = 7.84 degrees
M cancels out.
sinA = (1/2)Vmax^2/(g*135)
= 0.1364
A = 7.84 degrees
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.