Question
Skip designs tracks for amusement parks. For a new design the track will be ellipitical if the ellipse is placed on a large coordinate grid with its center at (0,0) the equation x^2/2500+y^2/8100=1 model the path of the park.The units are given in yards, how long is the major axis of the track?
Please help me
Please help me
Answers
Kiwi
This is very late so for people who might need it at some point here's what I did:
The larger denominator is under y so the ellipse is going to be vertical.
Equation: (x-h)^2/b^2 + (y-k)^2/a^2 =1
The center is (0,0) right so both h and k will be 0
a is the length of the major axis
b is the length of the minor axis
x^2/50^2 + y^2/90^2 = 1
x^2/50^2 + y^2/90^2 = 1
a=90
90 x 2 is 180
The major axis' length is going to be 180 yards.
The larger denominator is under y so the ellipse is going to be vertical.
Equation: (x-h)^2/b^2 + (y-k)^2/a^2 =1
The center is (0,0) right so both h and k will be 0
a is the length of the major axis
b is the length of the minor axis
x^2/50^2 + y^2/90^2 = 1
x^2/50^2 + y^2/90^2 = 1
a=90
90 x 2 is 180
The major axis' length is going to be 180 yards.
a Human
thankfully this is also relevant 2023! Thanks Kiwi!
A Human
anyone realize this was asked in 2013?