Asked by Jane
A rectangle has a length of 6x^3 y^2 - 1 and a width of 3xy + 2. The formula for the perimeter of a rectangle is P=2l + 2w, where l is the length and w is the width. What is the perimeter of the rectangle? Simplify your answer.
Answers
Answered by
Bosnian
P = 2 l + 2 w
P = 2 ( l + w )
P = 2 ( 6 x ^ 3 y ^ 2 - 1 + 3 x y + 2 )
P = 2 ( 6 x ^ 3 y ^ 2 + 3 x y + 1 )
P = 2 ( l + w )
P = 2 ( 6 x ^ 3 y ^ 2 - 1 + 3 x y + 2 )
P = 2 ( 6 x ^ 3 y ^ 2 + 3 x y + 1 )
Answered by
Bosnian
OR
P = 2 ( 6 x ^ 3 y ^ 2 + 3 x y + 1 )
P = 12 x ^ 3 y ^ 2 + 6 x y + 2
P = x y ( 12 x ^ 2 y + 6 ) + 2
P = 2 ( 6 x ^ 3 y ^ 2 + 3 x y + 1 )
P = 12 x ^ 3 y ^ 2 + 6 x y + 2
P = x y ( 12 x ^ 2 y + 6 ) + 2
Answered by
Bosnian
OR
P = 6 x y ( 2x ^ 2 y + 1 ) + 2
P = 6 x y ( 2x ^ 2 y + 1 ) + 2
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