C2H5OH + 3O2 ==> 2CO2 + 3H2O
mols C2H5OH = grams/molar mass
Convert mols C2H5OH to mols O2 using the coefficients in the balanced equation.
Now convert mols O2 to grams. g = mols x molar mass.
how many grams of dioxygen are required to burn 5.9 grams of C2H5OH?
2 answers
C2H5OH(l) +3O2(g)> 2CO2(g) +3H2O(l)
RFM of C2H5OH = (2×12)+(5×1)+16+1
=24+5+16+1
=46
No of moles= mass/RFM
No of moles of C2H5OH =5.9/46
=0.1283 moles
Mole ratio of C2H5OH to O2 is 1:3
No of moles of O2 =3/1×0.1283
=0.3849 moles
Mass= No of moles×molar mass
=0.3849×16
=6.1584g
RFM of C2H5OH = (2×12)+(5×1)+16+1
=24+5+16+1
=46
No of moles= mass/RFM
No of moles of C2H5OH =5.9/46
=0.1283 moles
Mole ratio of C2H5OH to O2 is 1:3
No of moles of O2 =3/1×0.1283
=0.3849 moles
Mass= No of moles×molar mass
=0.3849×16
=6.1584g
0 answers