A reaction rate increases by 60.3% when the temperature is increased from 21.5 to 35.6°C. Calculate the activation energy (in kJ/mol) for the reaction.

Answer 1

Give an arbitrary rate to the reaction at the 21.5C

Lets say it is 100 moles/sec
Then the rate at 35.6 is 160.3 M/s

Now, take the natural log of each of those rates.

Plot ln rate vs 1/tempinKelvins

The slope of that line is Ea/R where R is the universal gas constant.