In acute triangle ABC, we have \angle CAB = 34 ^\circ . E is the foot of the perpendicular from B to AC. A point H is on BE is chosen, and X is the foot of the perpendicular from H to AB. What is the measure (in degrees) of \angle EHX?

Answer 1

From X drop a perpendicular to intersect AC at Y.

XY ║ BX

Draw the diagram and it should be easy to see that EHX = 180-34 = 143

Answer 2

Sorry, that's

XY ║ BE