Asked by nikita
Construct a sign chart for the derivative. Then determine the relative and absolute extrema for
y = -4x2 + 4 on the interval [-3,3].
y = -4x2 + 4 on the interval [-3,3].
Answers
Answered by
bobpursley
y'=-8x
when x is negative, y' is +
when x is +, y' is negative
when x is negative, y' is +
when x is +, y' is negative
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