mols LiCl = grams/molar mass.
Solve for mols.
m = mols/kg solvent
Solve for m
delta T = i*Kf*m
Solve for delta T and subtract from norma freezing point. i for LiCl = 2.
what is the freezing point of 16.7g of LiCl in 136g of water, assuming complete dissociation for water kf= -1.86/mol
1 answer