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Asked by Alicia

Using the balanced equation of:
HCl+NaOH-->H20+NaCl, how many moles of HCl could be neutralized with 13.2 mL of 3.00 M NaOH?
12 years ago

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Answered by DrBob222
mols NaOH = M x L = ?
mols HCl = mols NaOH
12 years ago
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Using the balanced equation of:
HCl+NaOH-->H20+NaCl, how many moles of HCl could be neutralized with 13.2 mL of 3.00 M NaOH?

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