Asked by Anonymous
Please show work.
2Al(s) + 2NaOH(aq) + 6H2O(l) ---> 2NaAl(OH)4(aq) + 3H2(g)
What mass of hydrogen gas would be formed from a reaction of 2.48 g Al and 4.76 g NaOH in water?
Pb(NO3)2(s) + 2NaI(aq) ----> 2PbI2(s) +2NaNo3(aq)
(a) If the solution contains 7.00 g NaI, what mass of Pb(NO3)2 should be added to remove all the iodide ion from solution?
(b) When enough Pb(NO3)2 is added so that all 7.00g of NaI reacts, what mass of PbI2 should precipitate?
2Al(s) + 2NaOH(aq) + 6H2O(l) ---> 2NaAl(OH)4(aq) + 3H2(g)
What mass of hydrogen gas would be formed from a reaction of 2.48 g Al and 4.76 g NaOH in water?
Pb(NO3)2(s) + 2NaI(aq) ----> 2PbI2(s) +2NaNo3(aq)
(a) If the solution contains 7.00 g NaI, what mass of Pb(NO3)2 should be added to remove all the iodide ion from solution?
(b) When enough Pb(NO3)2 is added so that all 7.00g of NaI reacts, what mass of PbI2 should precipitate?
Answers
Answered by
Anonymous
I have no idea
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