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To find the acceleration of the water rocket, we can use the equation of motion:
v = u + at
Where:
v is the final velocity (in this case, zero),
u is the initial velocity (25 m/s),
a is the acceleration we are looking for, and
t is the time taken (2.5 s).
Since the rocket reaches its maximum height and its velocity becomes zero, we can rewrite the equation as:
0 = 25 + a * 2.5
Now, let's solve for the acceleration (a).
Subtracting 25 from both sides, we get:
-25 = 2.5a
Dividing both sides by 2.5:
a = -10 m/s^2
So, the acceleration of the water rocket is -10 m/sĀ². Since acceleration is defined as the rate of change of velocity, a negative acceleration indicates deceleration, which means the rocket is slowing down.