Asked by adex

Determine the minimum electric potential difference (in volts) that must be applied to accelerate an α-particle so that on interaction with a hydrogen atom, a ground state electron will be excited to n = 6.

Answers

Answered by Anonymous
You can use the following to solve the problem:
E = q*V
E = -K*(1/n1^2 - 1/n2^2)
q*V = -K*(1/n1^2 - 1/n2^2)
q = +2e
K = 8.987e9 Nm^2/C

Answer: 6.60625 volts
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