Asked by adex
Determine the minimum electric potential difference (in volts) that must be applied to accelerate an α-particle so that on interaction with a hydrogen atom, a ground state electron will be excited to n = 6.
Answers
Answered by
Anonymous
You can use the following to solve the problem:
E = q*V
E = -K*(1/n1^2 - 1/n2^2)
q*V = -K*(1/n1^2 - 1/n2^2)
q = +2e
K = 8.987e9 Nm^2/C
Answer: 6.60625 volts
E = q*V
E = -K*(1/n1^2 - 1/n2^2)
q*V = -K*(1/n1^2 - 1/n2^2)
q = +2e
K = 8.987e9 Nm^2/C
Answer: 6.60625 volts
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.