Question
Determine the minimum electric potential difference (in volts) that must be applied to accelerate an α-particle so that on interaction with a hydrogen atom, a ground state electron will be excited to n = 6.
Answers
Anonymous
You can use the following to solve the problem:
E = q*V
E = -K*(1/n1^2 - 1/n2^2)
q*V = -K*(1/n1^2 - 1/n2^2)
q = +2e
K = 8.987e9 Nm^2/C
Answer: 6.60625 volts
E = q*V
E = -K*(1/n1^2 - 1/n2^2)
q*V = -K*(1/n1^2 - 1/n2^2)
q = +2e
K = 8.987e9 Nm^2/C
Answer: 6.60625 volts