Question
Consider the heterogeneous equilibrium process shown below.
C(s) + CO2(g) 2 CO(g)
At 700.°C, the total pressure of the system is found to be 3.87 atm. If the equilibrium constant KP is 1.52, calculate the equilibrium partial pressures of CO2 and CO.
C(s) + CO2(g) 2 CO(g)
At 700.°C, the total pressure of the system is found to be 3.87 atm. If the equilibrium constant KP is 1.52, calculate the equilibrium partial pressures of CO2 and CO.
Answers
I assume that at equilibrium Ptotal = 3.87 atm.
.........C(s) + CO2(g) ==> 2CO(g)
E...............3.87-p......p..
If Ptotal = 3.87, if we call CO p then CO2 is 3.87-p. Substitute into Kp expression and solve.
.........C(s) + CO2(g) ==> 2CO(g)
E...............3.87-p......p..
If Ptotal = 3.87, if we call CO p then CO2 is 3.87-p. Substitute into Kp expression and solve.
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